Solution: Chain Rule #4

Solution: Chain Rule #4

Find the derivative of:

[latex]\Large{f(x) = e^{1-x^2}}[/latex]

Step 1:

 

We notice that the given function is a composite function, or a function within another function. To find the derivative of composite functions, we will use the chain rule. We can see that the inner function is [latex]1-x^2[/latex] and the outer function is the the exponential function.

 

The chain rule states:

 

[latex]\Large{\frac{d}{dx}f(g(x)) = f'(g(x)) \cdot g'(x)}[/latex]

 

Step 2:

 

Applying the chain rule, we have:

 

[latex]\Large{\frac{d}{dx}(e^{1-x^2}) = e^{1-x^2} \cdot \frac{d}{dx}(1-x^2)}[/latex]

 

Step 3:

 

Simplifying, we have:

 

[latex]\Large{ = -2xe^{1-x^2}}[/latex]

 

Thus, this is the final answer for the derivative. So:

 

[latex]\Large{f'(x) = -2xe^{1-x^2}}[/latex]

 

Solution Complete!

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Solution: Chain Rule #4

Find the derivative of:

[latex]\Large{f(x) = e^{1-x^2}}[/latex]

Step 1:

 

We notice that the given function is a composite function, or a function within another function. To find the derivative of composite functions, we will use the chain rule. We can see that the inner function is [latex]1-x^2[/latex] and the outer function is the the exponential function.

 

The chain rule states:

 

[latex]\Large{\frac{d}{dx}f(g(x)) = f'(g(x)) \cdot g'(x)}[/latex]

 

Step 2:

 

Applying the chain rule, we have:

 

[latex]\Large{\frac{d}{dx}(e^{1-x^2})}[/latex]

 

[latex]\Large{= e^{1-x^2} \cdot \frac{d}{dx}(1-x^2)}[/latex]

 

Step 3:

 

Simplifying, we have:

 

[latex]\Large{ = -2xe^{1-x^2}}[/latex]

 

Thus, this is the final answer for the derivative. So:

 

[latex]\Large{f'(x) = -2xe^{1-x^2}}[/latex]

 

Solution Complete!

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