Solution: Chain Rule #4
Solution: Chain Rule #4
Find the derivative of:
[latex]\Large{f(x) = e^{1-x^2}}[/latex]
Step 1:
We notice that the given function is a composite function, or a function within another function. To find the derivative of composite functions, we will use the chain rule. We can see that the inner function is [latex]1-x^2[/latex] and the outer function is the the exponential function.
The chain rule states:
[latex]\Large{\frac{d}{dx}f(g(x)) = f'(g(x)) \cdot g'(x)}[/latex]
Step 2:
Applying the chain rule, we have:
[latex]\Large{\frac{d}{dx}(e^{1-x^2}) = e^{1-x^2} \cdot \frac{d}{dx}(1-x^2)}[/latex]
Step 3:
Simplifying, we have:
[latex]\Large{ = -2xe^{1-x^2}}[/latex]
Thus, this is the final answer for the derivative. So:
[latex]\Large{f'(x) = -2xe^{1-x^2}}[/latex]
Solution Complete!
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Solution: Chain Rule #4
Find the derivative of:
[latex]\Large{f(x) = e^{1-x^2}}[/latex]
Step 1:
We notice that the given function is a composite function, or a function within another function. To find the derivative of composite functions, we will use the chain rule. We can see that the inner function is [latex]1-x^2[/latex] and the outer function is the the exponential function.
The chain rule states:
[latex]\Large{\frac{d}{dx}f(g(x)) = f'(g(x)) \cdot g'(x)}[/latex]
Step 2:
Applying the chain rule, we have:
[latex]\Large{\frac{d}{dx}(e^{1-x^2})}[/latex]
[latex]\Large{= e^{1-x^2} \cdot \frac{d}{dx}(1-x^2)}[/latex]
Step 3:
Simplifying, we have:
[latex]\Large{ = -2xe^{1-x^2}}[/latex]
Thus, this is the final answer for the derivative. So:
[latex]\Large{f'(x) = -2xe^{1-x^2}}[/latex]
Solution Complete!
Send us a review!
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