Solution: Evaluating Limits #1
Solution: Evaluating Limits #1
Evaluate the limit:
[latex]\Large{\lim_{x\to 3}\frac{5x^2-3x}{3x^3+3}}[/latex]
Step 1:
The first step is to always try solving the limit by direct substitution. So, we will substitute 3 into the function and see what we get.
[latex]\Large{\lim_{x\to 3}\frac{5x^2-3x}{3x^3+3} = \frac{5(3)^2 – 3(3)}{3(3)^3 + 3} = \frac{36}{84} = \frac{3}{7}}[/latex]
This was a simple problem which involved evaluating limits by direct substitution!
Solution Complete!
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Solution: Evaluating Limits #1
Evaluate the limit:
[latex]\Large{\lim_{x\to 3}\frac{5x^2-3x}{3x^3+3}}[/latex]
Step 1:
The first step is to always try solving the limit by direct substitution. So, we will substitute 3 into the function and see what we get.
[latex]\lim_{x\to 3}\frac{5x^2-3x}{3x^3+3} = \frac{5(3)^2 – 3(3)}{3(3)^3 + 3} = \frac{36}{84} = \frac{3}{7}[/latex]
This was a simple problem which involved evaluating limits by direct substitution!
Solution Complete!
Send us a review!
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