Solution: Derivative Power Rule #2
Solution: Derivative Power Rule #2
Find the derivative [latex]h'(x)[/latex] of:
[latex]\Large{h(x) = \frac{1}{h^2}} + \frac{3}{h^3}[/latex]
Step 1:
First, we will remove the fractions, by rewriting the function as follows:
[latex]\large{h'(x) = h^{-2} + 3h^{-3}}[/latex]
Notice that we can now use the derivative power rule to find the derivative.
Step 2:
Applying the power rule, we have:
[latex]\large{h'(x) = (-2)h^{-2-1} + 3(-3)h^{-3-1}}[/latex]
[latex]\large{h'(x) = -2h^{-3}\: -\: 9h^{-4}}[/latex]
Notice how we brought the exponent down and subtracted the exponent by 1.
Thus, we have:
[latex]\large{h'(x) = -\frac{2}{h^3}\: -\: \frac{9}{h^4}}[/latex]
This is our final answer for the derivative.
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Solution: Derivative Power Rule #2
Find the derivative [latex]h'(x)[/latex] of:
[latex]\Large{h(x) = \frac{1}{h^2}} + \frac{3}{h^3}[/latex]
Step 1:
First, we will remove the fractions, by rewriting the function as follows:
[latex]\large{h'(x) = h^{-2} + 3h^{-3}}[/latex]
Notice that we can now use the derivative power rule to find the derivative.
Step 2:
Applying the power rule, we have:
[latex]\large{h'(x) = (-2)h^{-2-1} + 3(-3)h^{-3-1}}[/latex]
[latex]\large{h'(x) = -2h^{-3}\: -\: 9h^{-4}}[/latex]
Notice how we brought the exponent down and subtracted the exponent by 1.
Thus, we have:
[latex]\large{h'(x) = -\frac{2}{h^3}\: -\: \frac{9}{h^4}}[/latex]
This is our final answer for the derivative.
Solution Complete!
Send us a review!
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