Solution: Derivative Power Rule #2

Solution: Derivative Power Rule #2

Find the derivative [latex]h'(x)[/latex] of:

[latex]\Large{h(x) = \frac{1}{h^2}} + \frac{3}{h^3}[/latex]

Step 1:

 

First, we will remove the fractions, by rewriting the function as follows:

 

[latex]\large{h'(x) = h^{-2} + 3h^{-3}}[/latex]

 

Notice that we can now use the derivative power rule to find the derivative.

 

Step 2:

 

Applying the power rule, we have:

 

[latex]\large{h'(x) = (-2)h^{-2-1} + 3(-3)h^{-3-1}}[/latex]

 

[latex]\large{h'(x) = -2h^{-3}\: -\: 9h^{-4}}[/latex]

 

Notice how we brought the exponent down and subtracted the exponent by 1.

 

Thus, we have:

 

[latex]\large{h'(x) = -\frac{2}{h^3}\: -\: \frac{9}{h^4}}[/latex]

 

This is our final answer for the derivative.

 

Solution Complete!

 

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Solution: Derivative Power Rule #2

Find the derivative [latex]h'(x)[/latex] of:

[latex]\Large{h(x) = \frac{1}{h^2}} + \frac{3}{h^3}[/latex]

Step 1:

 

First, we will remove the fractions, by rewriting the function as follows:

 

[latex]\large{h'(x) = h^{-2} + 3h^{-3}}[/latex]

 

Notice that we can now use the derivative power rule to find the derivative.

 

Step 2:

 

Applying the power rule, we have:

 

[latex]\large{h'(x) = (-2)h^{-2-1} + 3(-3)h^{-3-1}}[/latex]

 

[latex]\large{h'(x) = -2h^{-3}\: -\: 9h^{-4}}[/latex]

 

Notice how we brought the exponent down and subtracted the exponent by 1.

 

Thus, we have:

 

[latex]\large{h'(x) = -\frac{2}{h^3}\: -\: \frac{9}{h^4}}[/latex]

 

This is our final answer for the derivative.

 

Solution Complete!

 

Send us a review!

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