Solution: Chain Rule #5
Solution: Chain Rule #5
Find the derivative of:
[latex]\Large{g(x) = \cos(\ln(x))}[/latex]
Step 1:
We notice that the given function is a composite function, or a function within another function. To find the derivative of composite functions, we will use the chain rule. We can see that the inner function is [latex]\ln(x)[/latex] and the outer function is the cosine function.
The chain rule states:
[latex]\Large{\frac{d}{dx}f(g(x)) = f'(g(x)) \cdot g'(x)}[/latex]
Step 2:
Applying the chain rule, we have:
[latex]\Large{\frac{d}{dx}\cos(\ln(x)) = -\sin(\ln(x)) \cdot \frac{d}{dx}(\ln(x))}[/latex]
Step 3:
Simplifying, we have:
[latex]\Large{ = -\sin(\ln(x)) \cdot \frac{1}{x}}[/latex]
[latex]\Large{ = \frac{\sin(\ln(x))}{x}}[/latex]
Thus, this is the final answer for the derivative. So:
[latex]\Large{g'(x) = \frac{\sin(\ln(x))}{x}}[/latex]
Solution Complete!
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Solution: Chain Rule #5
Find the derivative of:
[latex]\Large{g(x) = \cos(\ln(x))}[/latex]
Step 1:
We notice that the given function is a composite function, or a function within another function. To find the derivative of composite functions, we will use the chain rule. We can see that the inner function is [latex]\ln(x)[/latex] and the outer function is the cosine function.
The chain rule states:
[latex]\Large{\frac{d}{dx}f(g(x)) = f'(g(x)) \cdot g'(x)}[/latex]
Step 2:
Applying the chain rule, we have:
[latex]\large{\frac{d}{dx}\cos(\ln(x))}[/latex]
[latex]\large{ = -\sin(\ln(x)) \cdot \frac{d}{dx}(\ln(x))}[/latex]
Step 3:
Simplifying, we have:
[latex]\Large{ = -\sin(\ln(x)) \cdot \frac{1}{x}}[/latex]
[latex]\Large{ = \frac{\sin(\ln(x))}{x}}[/latex]
Thus, this is the final answer for the derivative. So:
[latex]\Large{g'(x) = \frac{\sin(\ln(x))}{x}}[/latex]
Solution Complete!
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