Solution: Derivative Power Rule #4
Solution: Derivative Power Rule #4
Given: [latex]\Large{y = 3x^4-\frac{5}{x^3}+2x^2+3}[/latex]
Find [latex]\Large{\frac{dy}{dx}}[/latex]
Step 1:
First, we will remove the fraction, by rewriting the function as follows:
[latex]\large{y = 3x^4-5x^{-3}+2x^2+3}[/latex]
Notice that we can now use the derivative power rule to find the derivative.
Step 2:
Applying the power rule, we have:
[latex]\large{\frac{dy}{dx} = (3)x^{4-1} – 5(-3)x^{-3-1} + 2(2)x^{2-1}}[/latex]
[latex]\large{\frac{dy}{dx} = 3x^3 +15x^{-4}+4x}[/latex]
Notice how we brought the exponent down and subtracted the exponent by 1.
Thus, we have:
[latex]\large{\frac{dy}{dx} = 3x^3 + \frac{15}{x^4} + 4x}[/latex]
This is our final answer for the derivative.
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Solution: Derivative Power Rule #4
Given: [latex]\Large{y = 3x^4-\frac{5}{x^3}+2x^2+3}[/latex]
Find [latex]\Large{\frac{dy}{dx}}[/latex]
Step 1:
First, we will remove the fraction, by rewriting the function as follows:
[latex]\large{y = 3x^4-5x^{-3}+2x^2+3}[/latex]
Notice that we can now use the derivative power rule to find the derivative.
Step 2:
Applying the power rule, we have:
[latex]\small{\frac{dy}{dx} = (3)x^{4-1} – 5(-3)x^{-3-1} + 2(2)x^{2-1}}[/latex]
[latex]\large{\frac{dy}{dx} = 3x^3 +15x^{-4}+4x}[/latex]
Notice how we brought the exponent down and subtracted the exponent by 1.
Thus, we have:
[latex]\large{\frac{dy}{dx} = 3x^3 + \frac{15}{x^4} + 4x}[/latex]
This is our final answer for the derivative.
Solution Complete!
Send us a review!
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