Solution: Derivative Power Rule #5
Solution: Derivative Power Rule #5
Given: [latex]\Large{y = 7x^5-2x^4+3x^2+1}[/latex]
Find [latex]\Large{\frac{d^2y}{dx^2}}[/latex]
Step 1:
We can use the derivative power rule to find the derivative of the given function. We have:
[latex]\large{\frac{dy}{dx} = 7(5)x^{5-1}-2(4)x^{4-1}+3(2)x^{2-1}}[/latex]
Notice that we brought down the exponent, and subtracted the exponent by 1 for each term.
Step 2:
Now, after simplifying, we have:
[latex]\large{\frac{dy}{dx} = 35x^4-8x^3+6x}[/latex]
This is the first derivative.
We are not done yet since we need to find [latex]\frac{d^2y}{dx^2}[/latex] which is the second derivative.
Step 3:
Thus, using the power rule once more, we have:
[latex]\large{\frac{d^2y}{dx^2} = 35(4)x^{4-1}-8(3)x^{3-1}+6(1)x^{1-1}}[/latex]
[latex]\large{\frac{d^2y}{dx^2} = 140x^3 – 24x^2 + 6}[/latex]
Solution Complete!
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Solution: Derivative Power Rule #5
Given: [latex]\Large{y = 7x^5-2x^4+3x^2+1}[/latex]
Find [latex]\Large{\frac{d^2y}{dx^2}}[/latex]
Step 1:
We can use the derivative power rule to find the derivative of the given function. We have:
[latex]\small{\frac{dy}{dx} = 7(5)x^{5-1}-2(4)x^{4-1}+3(2)x^{2-1}}[/latex]
Notice that we brought down the exponent, and subtracted the exponent by 1 for each term.
Step 2:
Now, after simplifying, we have:
[latex]\large{\frac{dy}{dx} = 35x^4-8x^3+6x}[/latex]
This is the first derivative.
We are not done yet since we need to find [latex]\frac{d^2y}{dx^2}[/latex] which is the second derivative.
Step 3:
Thus, using the power rule once more, we have:
[latex]\small{\frac{d^2y}{dx^2} = 35(4)x^{4-1}-8(3)x^{3-1}+6(1)x^{1-1}}[/latex]
[latex]\large{\frac{d^2y}{dx^2} = 140x^3 – 24x^2 + 6}[/latex]
Solution Complete
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